49x^2+0x-9=0

Solution for 49x^2+0x-9=0 equation:

49x^2+0x-9=0

We add all the numbers together, and all the variables

49x^2+x-9=0

a = 49; b = 1; c = -9;
Δ = b2-4ac
Δ = 12-4·49·(-9)
Δ = 1765
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1765}}{2*49}=\frac{-1-\sqrt{1765}}{98}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1765}}{2*49}=\frac{-1+\sqrt{1765}}{98}
$